Solve each of the following systems of equations by the method of cross-multiplication:
Question:

Solve each of the following systems of equations by the method of cross-multiplication:

$x+2 y+1=0$

$2 x-3 y-12=0$

Solution:

GIVEN: 

$x+2 y+1=0$

 

$2 x-3 y-12=0$

To find: The solution of the systems of equation by the method of cross-multiplication:

By cross multiplication method we get

and $y=\frac{14}{-7}=-2$

Hence we get the value of $x=3$ and $y=-2$

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