Question:
Solve each of the following systems of equations by the method of cross-multiplication:
$x+2 y+1=0$
$2 x-3 y-12=0$
Solution:
GIVEN:
$x+2 y+1=0$
$2 x-3 y-12=0$
To find: The solution of the systems of equation by the method of cross-multiplication:
By cross multiplication method we get
and $y=\frac{14}{-7}=-2$
Hence we get the value of $x=3$ and $y=-2$
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