Question:
$\frac{2 x-3}{4 x+5}=\frac{1}{3}$
Solution:
Given, $\frac{2 x-3}{4 x+5}=\frac{1}{3}$
$\Rightarrow$ $3(2 x-3)=4 x+5$ [by cross-multiplication]
$\Rightarrow \quad 6 x-9=4 x+5$
$\Rightarrow$ $6 x-4 x=9+5 \quad$ [transposing $4 x$ to LHS and $-9$ to RHS]
$\Rightarrow$ $2 x=14$
$\Rightarrow$ $\frac{2 x}{2}=\frac{14}{2}$ [dividing both sides by 2]
$\therefore$ $x=7$
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