Question:
Solve the differential equation (1 + y2) tan–1x dx + 2y (1 + x2) dy = 0.
Solution:
Given differential equation, (1 + y2) tan–1x dx + 2y (1 + x2) dy = 0
2y (1 + x2) dy = -(1 + y2) tan-1x dx
Thus, the above equation is the required solution.
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