Question:
Solve the equation $x^{2}+3 x+5=0$
Solution:
The given quadratic equation is $x^{2}+3 x+5=0$
On comparing the given equation with $a x^{2}+b x+c=0$, we obtain
$a=1, b=3$, and $c=5$
Therefore, the discriminant of the given equation is
$\mathrm{D}=b^{2}-4 a c=3^{2}-4 \times 1 \times 5=9-20=-11$
Therefore, the required solutions are
$\frac{-b \pm \sqrt{D}}{2 a}=\frac{-3 \pm \sqrt{-11}}{2 \times 1}=\frac{-3 \pm \sqrt{11} i}{2}$ $[\sqrt{-1}=i]$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.