Solve the following :


The angle between the resultant contact force and the normal force exerted by a body on the other is called the angle of friction. Show that if $\lambda$ be the angle of friction and $\mu$ the coefficient of static friction, $\lambda$ $\leq \tan -1 \mu$


Angle of friction, $\tan \lambda=\frac{f f}{N}$

The value of friction force depends upon external force applied. If the body does not move then

$(f f=F)<(f f(I m)=\mu N)$

When body is about to move or moves then $\mathrm{ff}=f_{(l m)}=\mu \mathrm{N}$


$\mathrm{ff}<=\mu N$

$\therefore \tan \lambda \leq \frac{\mu N}{N}$

$\tan \lambda \leq \mu$

$\lambda \leq \tan ^{-1}(\mu)$


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now