Solve the following :

Question:

A cylinder rolls on a horizontal plane surface. If the speed of the centre is $25 \mathrm{~m} / \mathrm{s}$, what is the speed of the highest point?

Solution:

For pure rolling

$v_{C}=R \omega$

Speed at highest point= $\mathrm{v}+\quad R \omega$

$=2 \mathrm{v}$

$=2(25)$

$=50 \mathrm{~m} / \mathrm{s}$

 

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