Solve the following :


A boy is standing on a long railroad car throws a ball straight upwards. The car is moving on the horizontal road with an acceleration of $1 \mathrm{~m} / \mathrm{s}^{2}$ and the projection velocity in the vertical direction is $9.8$ $\mathrm{m} / \mathrm{s}$. How far behind the boy will the ball fall on the car?


$\underline{2 u \sin \theta}$

Time of flight for ball $=$ g

$=\frac{2(9.8) \sin 9 \overline{0}^{-}}{\text {E }}$

$t=2 \sec$

For ball-car, along horizontal direction

$u_{r e l}=0$

$a_{r e l}=1$


$\mathrm{S}_{\mathrm{rel}}=\mathrm{U}_{\mathrm{rel}} t_{+} \frac{1}{2} \mathrm{a}_{\mathrm{rel}} t^{2}$


$\mathrm{s}_{\mathrm{rel}}=2 \mathrm{~m}$

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