Solve the following :

$\operatorname{Tan} \theta=228 / 171=4 / 3$

$\theta=53^{\circ}$

$x$-axis $y$-axis

$u_{x}=15 \sin 53 u_{y}=15 \cos 53$

$u_{x}=12 \mathrm{ft} / \mathrm{sec} \mathrm{u}_{\mathrm{y}}=9 \mathrm{ft} / \mathrm{sec}$

$a_{y}=32 \mathrm{ft} / \mathrm{sec}^{2}$

$s_{y}=171 \mathrm{ft}$

$s_{y}=u_{y} t+\frac{1}{2} a_{y} t^{2}$

$171=9 t+^{\frac{1}{2}}(32) t^{2}$

$t=3$ sec

$s_{x}=12 \times 3$

$=36 \mathrm{ft}$

Packet will fall short by $=228-36=192 \mathrm{ft}$