Solve the following :

Question:

A uniform metre stick of mass $200 \mathrm{~g}$ is suspended from the ceiling through two vertical strings of equal lengths fixed at the ends. A small object of mass $20 \mathrm{~g}$ is placed on the stick at a distance of 70 $\mathrm{cm}$ from the left end. Find the tensions in the two strings.

Solution:

Translatory Equilibrium Equation

$T_{1}+T_{2}=(0.2 g)+(0.02 g)$

$T_{1}+T_{2}=0.22 g$

Rotational Equilibrium Equation at point $A$ clockwise Torque= anticlockwise Torque

$(0.2 g)+(0.5)+(0.02 g)(0.7)={ }^{T} 2(1)$

$T_{2}=1.12 \mathrm{~N}$

From (i) $T_{1}=1.04 \mathrm{~N}$

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