Solve the following :


A bullet travelling with a velocity of $16 \mathrm{~m} / \mathrm{s}$ penetrates a tree trunk and comes to rest in $0.4 \mathrm{~m}$. Find the time taken during the retardation.


$\mathrm{u}=16 \mathrm{~m} / \mathrm{s} ; \mathrm{v}=0 \mathrm{~m} / 2 ; \mathrm{s}=0.4 \mathrm{~m}$

$v^{2}=u^{2}+2 a s$


$a=-320 m / s^{2}$

$\mathrm{v}=\mathrm{u}+$ at

$0=16+(-320) t$

$t=0.05 \mathrm{sec}$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now