Question:
When a person leaves his home for sightseeing by his car, the meter reads $12352 \mathrm{~km}$. When he returns home after two hours the reading is $12416 \mathrm{~km}$.
(a) What is the average speed of the car during the period?
(b) What is the average velocity?
Solution:
(a) $\mathrm{g}=\frac{\text { Total distance }}{\text { time }}=\frac{(12416-12352)}{2}$
(b) $\overrightarrow{\mathrm{V}} \mathrm{avg}^{\prime}=$ displacement/time
$\vec{V}_{\text {avg }}=0$
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