Solve the following :

Question:
A block of $2 \mathrm{~kg}$ is suspended from the ceiling through a mass less spring of spring constant $\mathrm{k}=100$ $\mathrm{N} / \mathrm{m}$. What is the elongation of the spring? If another $1 \mathrm{~kg}$ is added to the block, what would be the further elongation?

Solution:

$1^{\text {st }}$ Case:

mq=-kx

$x=\frac{-m g}{k}=\frac{-2 \times 9 .}{100}$

$=-0.196 m=-0.2 m$

2nd $^{\text {nd }}$ Case:

$m=3 k g$

$x^{\prime}=\frac{-3 \times 9.8}{100}=-0.294 m=-0.3 m$

$\left|x^{\prime}-x\right|=0.1 m$

Solve the following :

Leave a comment

All Study Material