Question:
Solve the following quadratic equations by factorization:
(2x + 3)(3x − 7) = 0
Solution:
We have been given,
$(2 x+3)(3 x-7)=0$
Therefore,
$(2 x+3)=0$
$2 x=-3$
$x=\frac{-3}{2}$
or
$(3 x-7)=0$
$3 x=7$
$x=\frac{7}{3}$
Therefore, $x=\frac{-3}{2}$ or $x=\frac{7}{3}$.
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