Question:
Solve the following systems of equations:
$\sqrt{2} x-\sqrt{3} y=0$
$\sqrt{3} x-\sqrt{8} y=0$
Solution:
The given equations are:
$\sqrt{2} x-\sqrt{3} y=0 \ldots(i)$
$\sqrt{3} x-\sqrt{8} y=0 \ldots($ ii $)$
Multiply equation $(i)$ by $\sqrt{3}$ and equation $(i i)$ by $\sqrt{2}$ and subtract equation (ii) from (i), we get
$\sqrt{6} x-3 y=0$
$\Rightarrow y=0$
Put the value of $y$ in equation $(i)$, we get
$\sqrt{2} x+0 \times y=0$
$\Rightarrow x=0$
Hence the value of $x=0$ and $y=0$
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