# Solve the following systems of equations:

Question:

Solve the following systems of equations:

$3 x-7 y+10=0$

$y-2 x-3=0$

Solution:

The given equations are:

$3 x-7 y+10=0$...(i)

$y-2 x-3=0$...(ii)

Multiply equation (i) by 2 and equation (ii) by 3 , and add both equations we get

Put the value of $y$ in equation $(i)$ we get

$3 x-7 \times 1+10=0$

$\Rightarrow 3 x=-3$

$\Rightarrow x=-1$

Hence the value of $x=-1$ and $y=1$