Solve this


Let $f: R^{+} \rightarrow R: f(x)=\log _{e} x .$ Find $\{x: f(x)=-2\}$



Given, $f: R^{+} \rightarrow R: f(x)=\log _{e} x$


$\log _{e} x=-2$

Taking antilog on both sides


Hence, the value of $x$ for which $f(x)=-2$ is $e^{-2}$.


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