Solve this
Question:

$\frac{1}{(3+2 \sqrt{2})}=?$

(a) $\frac{3-2 \sqrt{2}}{17}$

(b) $\frac{(3-2 \sqrt{2})}{13}$

(c) $(3-2 \sqrt{2})$

(d) None of these

 

Solution:

$\frac{1}{(3+2 \sqrt{2})}=\frac{1}{(3+2 \sqrt{2})} \times \frac{(3-2 \sqrt{2})}{(3-2 \sqrt{2})}=\frac{(3-2 \sqrt{2})}{9-8}=(3-2 \sqrt{2})$

Hence, the correct answer is option (c). 

 

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