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If $A=\left\{\frac{1}{x}: x \in N\right\}$ and $\left.x<8\right\}$, and $B=\left\{\frac{1}{2 x}: x \in N\right.$ and $\left.x \leq 4\right\}$, find :

(i) $A \cup B$

(ii) $\mathbf{A} \cap \mathbf{B}$

(iii) $A-B$

(vi) $\mathbf{B}-\mathbf{A}$



Given; $A=\left\{\frac{1}{x}: x \in N\right\}$ and $\mathrm{x}<8$ and $B=\left\{\frac{1}{2 x}: x \in N\right\}$ and $\mathrm{x} \leq 4$

According to the given conditions;

$A=\left\{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \frac{1}{6}, \frac{1}{7}\right\}$ and $B=\left\{\frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \frac{1}{8}\right\}$

(i) $A \cup B=$

$\left\{1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \frac{1}{6}, \frac{1}{7}, \frac{1}{8}\right\}$

(ii) $A \cap B=$

$\left\{\frac{1}{2}, \frac{1}{4}, \frac{1}{6}\right\}$

(iii) $A-B=$

$\left\{1, \frac{1}{3}, \frac{1}{5}, \frac{1}{7}\right\}$

(vi) $\mathrm{B}-\mathrm{A}=$


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