Solve this
Question:

If $p(x)=x^{2}-2 \sqrt{2} x+1$, then $p(2 \sqrt{2})=$ ?

(a) 0

(b) 1

(c) $4 \sqrt{2}$

(d) $-1$

 

Solution:

(b) 1

$p(x)=x^{2}-2 \sqrt{2} x+1$

$\therefore p(2 \sqrt{2})=(2 \sqrt{2})^{2}-2 \sqrt{2} \times(2 \sqrt{2})+1$

$=8-8+1$

$=1$

 

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