# Solve this

Question:

$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}), \mathrm{K}_{1} \quad$ (A)

$\mathrm{N}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g}), \mathrm{K}_{2}$

$\mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g}), \mathrm{K}_{3}$

The equation for the equilibrium constant of the reaction

$2 \mathrm{NH}_{3}(\mathrm{~g})+\frac{5}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})+3 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}),\left(\mathrm{K}_{4}\right)$

in terms of $K_{1}, K_{2}$ and $K_{3}$ is :

1. $\frac{\mathrm{K}_{1} \mathrm{~K}_{3}^{2}}{\mathrm{~K}_{2}}$

2. $\frac{\mathrm{K}_{2} \mathrm{~K}_{3}^{3}}{\mathrm{~K}_{1}}$

3. $\frac{K_{1} K_{2}}{K_{3}}$

4. $\mathrm{K}_{1} \mathrm{~K}_{2} \mathrm{~K}_{3}$

Correct Option: , 2

Solution:

Fact