Solve this


Solve $x+5>4 x-10$, when $x \in R$



$x+5>4 x-10$

$\Rightarrow 5+10>4 x-x$

$\Rightarrow 15>3 x$

Divide by 3

$\Rightarrow 5>x$

$\Rightarrow x<5$

$x<5$ means $x$ is from $-\infty$ to 5 that is $x \in(-\infty, 5)$

Hence solution of $x+5>4 x-10$ is $x \in(-\infty, 5)$


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