Solve this


$x-2 y=4$

$-3 x+5 y=-7$


Given: $\quad x-2 y=4$

$-3 x+5 y=-7$

Using the properties of determinants, we get

$\mathrm{D}=\mid \begin{array}{ll}1 & -2\end{array}$

$-3 \quad 5 \quad \mid=5-6=-1 \neq 0$

$\mathrm{D}_{1}=\mid 4 \quad-2$

$-7 \quad 5 \mid=20-14=6$

$\mathrm{D}_{2}=\mid 1 \quad 4$

$-3-7 \mid=-7+12=5$

Using Cramer's Rule, we get



$\therefore \mathrm{x}=-6$ and $\mathrm{y}=-5$

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