Solve this following

Question:

The empirical formula for a compound with a cubic close packed arrangement of anions and with cations occupying all the octahedral sites in $\mathrm{A}_{\mathrm{x}} \mathrm{B}$. The value of $\mathrm{x}$ is

(Integer answer)

Solution:

Anions froms $\mathrm{CCP}$ or $\mathrm{FCC}\left(\mathrm{A}^{-}\right)=4 \mathrm{~A}^{-}$per unit cell Cations occupy all octahedral voids $\left(\mathrm{B}^{+}\right)=4 \mathrm{~B}^{+}$per unit cell

cell formula $\rightarrow \mathrm{A}_{4} \mathrm{~B}_{4}$

Empirical formula $\rightarrow \mathrm{AB}$

$\rightarrow(\mathrm{x}=1)$

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