Question:
Find, when:
If $y \log x=(x-y)$, prove that $\frac{d y}{d x}=\frac{\log x}{(1+\log x)^{2}}$
Solution:
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Find, when:
If $y \log x=(x-y)$, prove that $\frac{d y}{d x}=\frac{\log x}{(1+\log x)^{2}}$