Solve this following


In the reported figure of earth, the value of acceleration due to gravity is same at point A and $\mathrm{C}$ but it is smaller than that of its value at point $B$ (surface of the earth). The value of OA : AB will be $x: y$. The value of $x$ is





$\frac{r}{R^{3}}=\frac{1}{\frac{9}{4} R^{2}} \Rightarrow r=\frac{4 R}{9}$

so $\mathrm{OA}=\frac{4 \mathrm{R}}{9} ; \mathrm{AB}=\mathrm{R}-\mathrm{r}=\frac{5 \mathrm{R}}{9}$

$\mathrm{OA}: \mathrm{AB}=4: 5$

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