Solve this following


$T_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to

$\frac{1}{16}$ times of its initial value, the modified time period is:

  1. $\mathrm{T}_{0}$

  2. $8 \pi \mathrm{T}_{0}$

  3. $4 \mathrm{~T}_{0}$

  4. $\frac{1}{4} T_{0}$

Correct Option: , 4


$\mathrm{T}_{0}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}}}$

New time period $\mathrm{T}=2 \pi \sqrt{\frac{\ell / 16}{\mathrm{~g}}}=\frac{2 \pi}{4} \sqrt{\frac{\ell}{\mathrm{g}}}$


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