Solve this following
Question:

A bead of mass $m$ stays at point $P(a, b)$ on a wire bent in the shape of a parabola $\mathrm{y}=4 \mathrm{Cx}^{2}$ and rotating with angular speed $\omega$ (see figure). The value of $\omega$ is (neglect friction):

 

  1. $\sqrt{\frac{2 \mathrm{gC}}{\mathrm{ab}}}$

  2. $2 \sqrt{2 \mathrm{gC}}$

  3. $\sqrt{\frac{2 g}{\mathrm{C}}}$

  4. $2 \sqrt{\mathrm{gC}}$


Correct Option: , 2

Solution:

$x \omega^{2}=g \cdot \frac{d y}{d x}$

$x \omega^{2}=g .(8 c x)$

$\omega^{2}=8 \mathrm{gc}$

$\omega=2 \sqrt{2 \mathrm{gc}}$

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