Solve this following


Let $\mathrm{n}$ be a non-negative integer. Then the number of divisors of the form "4n + 1" of the number

$(10)^{10} \cdot(11)^{11} \cdot(13)^{13}$ is equal to _____________


$\mathrm{N}=2^{10} \times 5^{10} \times 11^{11} \times 13^{13}$

Now, power of 2 must be zero,

power of 5 can be anything,

power of 13 can be anything.

But, power of 11 should be even.

So, required number of divisors is

$1 \times 11 \times 14 \times 6=924$


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