Solve this following


For three events $A, B$ and $C$,

$P$ (Exactly one of $\mathrm{A}$ or $\mathrm{B}$ occurs)

$=\mathrm{P}($ Exactly one of $\mathrm{B}$ or $\mathrm{C}$ occurs $)$

$=\mathrm{P}($ Exactly one of $\mathrm{C}$ or A occurs $)=\frac{1}{4}$ and $\mathrm{P}($ All the three events occur simultaneously $)=\frac{1}{16}$.

Then the probability that at least one of the events occurs, is :-

  1. $\frac{3}{16}$

  2. $\frac{7}{32}$

  3. $\frac{7}{16}$

  4. $\frac{7}{64}$

Correct Option: , 3


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