Solve this following


A block of mass $m$ is placed on a surface with a vertical cross section given by $y=\frac{x^{3}}{6}$. If the coefficient of friction is $0.5$, the maximum height above the ground at which the block can be placed without slipping is :-


  1. $\frac{1}{3} m$

  2. $\frac{1}{2} \mathrm{~m}$

  3. $\frac{1}{6} m$

  4. $\frac{2}{3} m$

Correct Option: , 3


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