Solve this following


Let $P$ be the plane, which contains the line of intersection of the planes, $x+y+z-6=0$ and $2 \mathrm{x}+3 \mathrm{y}+\mathrm{z}+5=0$ and it is perpendicular to the $x y$-plane. Then the distance of the point $(0,0,256)$ from $P$ is equal to :-

  1. $63 \sqrt{5}$

  2. $205 \sqrt{5}$

  3. $17 / \sqrt{5}$

  4. $11 / \sqrt{5}$

Correct Option: , 4


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