Solve this following


If one of the diameters of the circle $x^{2}+y^{2}-2 x-6 y+6=0$ is a chord of another circle ' $C$ ', whose center is at $(2,1)$, then its radius is



$x^{2}+y^{2}+2 x-6 y+6=0$

center $(1,3)$

radius $=2$

distance between $(1,3)$ and $(2,1)$ is $\sqrt{5}$


$\Rightarrow \mathrm{r}=3$


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