Question:
Suppose the acceleration due to gravity at a place is $10 \mathrm{~m} / \mathrm{s}^{2}$. Find its value in $\mathrm{cm} /(\text { minute })^{2}$.
Solution:
$\mathrm{g}=10 \mathrm{metre} / \mathrm{sec}^{2}=10 \times 100 \times 3600 \mathrm{~cm} / \mathrm{min}^{2} .=36 \times 10^{5} \mathrm{~cm} / \mathrm{min}^{2}$
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