Tap A can fill a cistern in 8 hours and tap B can empty it in 12 hours.

Question:

Tap A can fill a cistern in 8 hours and tap B can empty it in 12 hours. How long will it take to fill the cistern if both of them are opened together?

Solution:

Tap A can fill a cistern in 8 hours.

Part of cistern filled by Tap A in 1 hour $=\frac{1}{8}$

Tap B empties the cistern in 12 hours.

Part of cistern emptied by Tap B in 1 hour $=-\frac{1}{12}$ (negative sign shows that tap B drains the tank)

Part of cistern filled in one hour when both taps are opened together $=\frac{1}{8}-\frac{1}{12}=\frac{3-2}{24}=\frac{1}{24}$

Therefore, it will take 24 hours to fill the cistern.

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