**Question:**

Team 'A' consists of 7 boys and $n$ girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then $\mathrm{n}$ is equal to :

Correct Option: , 3

**Solution:**

Total matches between boys of both team

$={ }^{7} \mathrm{C}_{1} \times{ }^{4} \mathrm{C}_{1}=28$

Total matches between girls of both

team $={ }^{n} \mathrm{C}_{1}{ }^{6} \mathrm{C}_{1}=6 \mathrm{n}$

Now, $28+6 \mathrm{n}=52$

$\Rightarrow \mathrm{n}=4$