The angular speed of truck

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Question:

The angular speed of truck wheel is increased from $900 \mathrm{rpm}$ to $2460 \mathrm{rpm}$ in 26 seconds. The number of revolutions by the truck engine during this time is

(Assuming the acceleration to be uniform).

Solution:

We know, $\theta=\left(\frac{\omega_{1}+\omega_{2}}{2}\right) \mathrm{t}$

Let number of revolutions be $\mathrm{N}$

$\therefore 2 \pi N=2 \pi\left(\frac{900+2460}{60 \times 2}\right) \times 26$

$\mathrm{N}=728$

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