Question:
The area (in sq. units) in the first quadrant bounded by the parabola, $\mathrm{y}=\mathrm{x}^{2}+1$, the tangent to it at the point $(2,5)$ and the coordinate axes is :-
Correct Option: , 3
Solution:
Area $=\int_{0}^{2}\left(x^{2}+1\right) d x-\frac{1}{2}\left(\frac{5}{4}\right)(5)=\frac{37}{24}$
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