The area (in sq. units) of the smaller of the two circles that touch the parabola
Question:

The area (in sq. units) of the smaller of the two circles that touch the parabola, $\mathrm{y}^{2}=4 \mathrm{x}$ at the point $(1,2)$ and the $x$-axis is :-

  1. $4 \pi(2-\sqrt{2})$

  2. $8 \pi(3-2 \sqrt{2})$

  3. $4 \pi(3+\sqrt{2})$

  4. $8 \pi(2-\sqrt{2})$


Correct Option: , 2

Solution:

 

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