The area of a trapezium is 960 cm

Given;

Area of the trapezium $=960 \mathrm{~cm}^{2}$

And the length of the parallel sides are $34 \mathrm{~cm}$ and $46 \mathrm{~cm}$.

Area of trapezium $=\frac{1}{2} \times($ Sum of the parallel sides $) \times($ Perpendicular distance between the parallel sides $)$

$\Rightarrow 960=\frac{1}{2} \times(34+46) \times($ Height $)$

$\Rightarrow 960=40 \times($ Height $)$

$\Rightarrow$ Height $=\frac{960}{40}=24 \mathrm{~cm}$