The area of the base of a right circular cylinder is 616 cm

Given:

Area of the base of a right circular cylinder $=616 \mathrm{~cm}^{2}$

Height $=2.5 \mathrm{~cm}$

Let $r$ be the radius of the base of a right circular cylinder.

$\pi \mathrm{r}^{2}=616$

$\Rightarrow \mathrm{r}^{2}=616 \times \frac{7}{22}$

$\Rightarrow \mathrm{r}^{2}=196$

$\Rightarrow \mathrm{r}=14 \mathrm{~cm}$

Curved surface area of the right circular cylinder $=2 \pi \mathrm{rh}=2 \times \frac{22}{7} \times 14 \times 2.5=220 \mathrm{~cm}^{2}$