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The bond order and magnetic

Question:

The bond order and magnetic behaviour of $\mathrm{O}_{2}^{-}$ion are, respectively:

  1. $1.5$ and paramagnetic

  2. $1.5$ and diamagnetic

  3. 2 and diamagnetic

  4. 1 and paramagnetic


Correct Option: 1

Solution:

$\mathrm{O}_{2}^{-}=\left(\sigma_{1 \mathrm{~s}}\right)^{2}\left(\sigma_{1 \mathrm{~s}}^{*}\right)^{2}\left(\sigma_{2 \mathrm{~s}}\right)^{2}\left(\sigma_{2 \mathrm{~s}}^{*}\right)^{2}\left(\sigma_{2 \mathrm{p}_{\mathrm{z}}}\right)^{2}$

$\left(\pi_{2 p_{x}}^{2}=\pi_{2 p_{y}}^{2}\right)\left(\pi_{2 p_{x}}^{* 2}=\pi_{2 p_{y}}^{*_{1}}\right)$

Bond order $=\frac{10-7}{2}=1.5$

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