Question:
The circumference of the base of a 10 m height conical tent is 44m, calculate the length of canvas used in making the tent if width of canvas is 2 m.
Solution:
We know that
C.S.A of cone = πrl
Given circumference = 2πr
⟹ 2 ∗ 227 ∗ r = 44
⟹ r/7 = 1
⟹ r = 7 m
Therefore
$\mathrm{l}=\sqrt{\mathrm{r}^{2}+\mathrm{h}^{2}}$
$=\sqrt{7^{2}+10^{2}}$
$\mathrm{l}=\sqrt{149} \mathrm{~m}$
Therefore C.S.A of tent = πrl
$=\frac{22}{7} * 7 * \sqrt{149}$
$=22 \sqrt{149}$
Therefore the length of canvas used in making the tent
$=\frac{\text { Area of canvas }}{\text { Width of canvas }}$
$=\frac{22}{2 \sqrt{149}}$
$=\frac{11}{\sqrt{149}}$
= 134.2 m
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- JEE Main
- Exam Pattern
- Previous Year Papers
- PYQ Chapterwise
- Physics
- Kinematics 1D
- Kinemetics 2D
- Friction
- Work, Power, Energy
- Centre of Mass and Collision
- Rotational Dynamics
- Gravitation
- Calorimetry
- Elasticity
- Thermal Expansion
- Heat Transfer
- Kinetic Theory of Gases
- Thermodynamics
- Simple Harmonic Motion
- Wave on String
- Sound waves
- Fluid Mechanics
- Electrostatics
- Current Electricity
- Capacitor
- Magnetism and Matter
- Electromagnetic Induction
- Atomic Structure
- Dual Nature of Matter
- Nuclear Physics
- Radioactivity
- Semiconductors
- Communication System
- Error in Measurement & instruments
- Alternating Current
- Electromagnetic Waves
- Wave Optics
- X-Rays
- All Subjects
- Physics
- Motion in a Plane
- Law of Motion
- Work, Energy and Power
- Systems of Particles and Rotational Motion
- Gravitation
- Mechanical Properties of Solids
- Mechanical Properties of Fluids
- Thermal Properties of matter
- Thermodynamics
- Kinetic Theory
- Oscillations
- Waves
- Electric Charge and Fields
- Electrostatic Potential and Capacitance
- Current Electricity
- Thermoelectric Effects of Electric Current
- Heating Effects of Electric Current
- Moving Charges and Magnetism
- Magnetism and Matter
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Wave
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- Atoms
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