The correct order for acid strength of compounds

Question:

The correct order for acid strength of compounds $\mathrm{CH} \equiv \mathrm{CH}, \mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$ and $\mathrm{CH}_{2}=\mathrm{CH}_{2}$ is as follows :

  1. $\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$

  2. $\mathrm{HC} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

  3. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{HC} \equiv \mathrm{CH}$

  4. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$


Correct Option: , 2

Solution:

$\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

(Acidic strength order)

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