# The correct order for acid strength of compounds

Question:

The correct order for acid strength of compounds $\mathrm{CH} \equiv \mathrm{CH}, \mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$ and $\mathrm{CH}_{2}=\mathrm{CH}_{2}$ is as follows :

1. $\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$

2. $\mathrm{HC} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

3. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{HC} \equiv \mathrm{CH}$

4. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

Correct Option: , 2

Solution:

$\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

(Acidic strength order)