Question:
The density of 3 molal solutions of NaOH is 1.110 g mL–1. Calculate the molarity
of the solution.
Solution:
3 molal solution of NaOH = 3 moles of NaOH dissolved in 1000g water
3 mole of NaOH = 3*40g = 120g
Density of solution = 1.110gmL-1
Volume = mass/density = 1120g/1.110gmL-1 =1.009L
Molarity of the solution = 3/1.009 = 2.97M
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