The density of 3 molal solutions


The density of 3 molal solutions of NaOH is 1.110 g mL–1. Calculate the molarity

of the solution.


3 molal solution of NaOH = 3 moles of NaOH dissolved in 1000g water

3 mole of NaOH = 3*40g = 120g

Density of solution = 1.110gmL-1

Volume = mass/density = 1120g/1.110gmL-1 =1.009L

Molarity of the solution = 3/1.009 = 2.97M

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