The density of a non-uniform rod of length 1 m is given by

Question:

The density of a non-uniform rod of length 1 m is given by $\rho(x)=a\left(1+b x^{2}\right)$ where $\mathrm{a}$ and $\mathrm{b}$ are constant and $0 \leq \mathrm{x} \leq 1$. The centre of mass of the rod will be at

(a) $\frac{3(2+b)}{4(3+b)}$

(b) $\frac{4(2+b)}{3(3+b)}$

(c) $\frac{3(3+b)}{4(2+b)}$

(d) $\frac{4(3+b)}{3(2+b)}$

Solution:

The correct answer is (a)

$\frac{3(2+b)}{4(3+b)}$

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