# The distantce of the point

Question:

The distantce of the point $(1,3,-7)$ from the plane passing through the point $(1,-1,-1)$, having

normal perpendicular to both the lines $\frac{x-1}{1}=\frac{y+2}{-2}=\frac{z-4}{3}$ and $\frac{x-2}{2}=\frac{y+1}{-1}=\frac{z+7}{-1}$, is :-

1. $\frac{10}{\sqrt{74}}$

2. $\frac{20}{\sqrt{74}}$

3. $\frac{10}{\sqrt{83}}$

4. $\frac{5}{\sqrt{83}}$

Correct Option: 1

Solution: