Question:
The domain of the function $f$ defined by $f(x)=\frac{1}{\sqrt{x-|x|}}$ is
(a) R0
(b) R+
(c) R−
(d) none of these
Solution:
$f(x)=f(x)=\frac{1}{\sqrt{x-|x|}}$
f(x) is defined if x − |x| > 0
i.e x > |x|
i.e |x| < x
Since no such real number x exist such that |x| < x
$\therefore$ Domain of $f(x)$ is empty set.
Hence, the correct answer is option D.
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