The equation of a circle is


The equation of a circle is

$\operatorname{Re}\left(z^{2}\right)+2(\operatorname{Im}(z))^{2}+2 \operatorname{Re}(z)=0$, where $z=x+i y$.

A line which passes through the center of the given circle and the vertex of the parabola, $x^{2}-6 x-y+13=0$, has $y$-intercept equal to_______.


Equation of circle is $\left(x^{2}-y^{2}\right)+2 y^{2}+2 x=0$

$x^{2}+y^{2}+2 x=0$

Centre: $(-1,0)$

Parabola : $x^{2}-6 x-y+13=0$


Vertex : $(3,4)$

Equation of line $\equiv y-0=\frac{4-0}{3+1}(x+1)$


$y$-intercept $=1$

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