Question:
The equation of the plane passing through the point $(1,2,-3)$ and perpendicular to the planes $3 x+y-2 z=5$ and $2 x-5 y-z=7$, is:
Correct Option: , 3
Solution:
Normal vector of required plane is $\vec{n}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 3 & 1 & -2 \\ 2 & -5 & -1\end{array}\right|=-11 \hat{i}-\hat{j}-17 \hat{k}$
$\therefore 11(x-1)+(y-2)+17(z+3)=0$
$11 x+y+17 z+38=0$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.