The equation of the tangent


The equation of the tangent at $(2,3)$ on the curve $y^{2}=a x^{3}+b$ is $y=4 x-5$. Find the values of $a$ and $b$.


finding the slope of the tangent by differentiating the curve

$2 y \frac{d y}{d x}=3 a x^{2}$

$\frac{d y}{d x}=\frac{3 a x^{2}}{2 y}$

$\mathrm{m}$ (tangent) at $(2,3)=2 \mathrm{a}$

equation of tangent is given by $y-y_{1}=m($ tangent $)\left(x-x_{1}\right)$

now comparing the slope of a tangent with the given equation

$2 a=4$


now $(2,3)$ lies on the curve, these points must satisfy

$3^{2}=2 \times 2^{3}+b$


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now